Understanding the Type and Hexadecimal Representation of the 'sw $t1, 32($t2)' Instruction: A Comprehensive Guide

In this guide, we will discuss the 'sw $t1, 32($t2)' instruction used in the MIPS Assembly language. We will cover the instruction type, hexadecimal representation, and a step-by-step breakdown of the encoding process. By the end, you should have a clear understanding of how this instruction works and how to represent it in hexadecimal format.

Table of Contents

  1. Introduction to MIPS Assembly Language
  2. Understanding the 'sw $t1, 32($t2)' Instruction
  3. Instruction Encoding
  1. FAQ
  2. Related Links

Introduction to MIPS Assembly Language

MIPS (Microprocessor without Interlocked Pipeline Stages) is a Reduced Instruction Set Computer (RISC) architecture that is widely used in embedded systems and academic settings. MIPS assembly language is a low-level programming language used to program MIPS processors.

For more information on MIPS Assembly Language, refer to the following resources:

Understanding the 'sw $t1, 32($t2)' Instruction

The 'sw $t1, 32($t2)' instruction is a Store Word (SW) instruction used to store a word (32 bits) of data from a source register ($t1) into memory. The memory address is calculated by adding the contents of the base register ($t2) to an immediate offset value (32 in this case).

The general format of the SW instruction is:

sw source_register, offset(base_register)

In our example, the instruction 'sw $t1, 32($t2)' stores the contents of register $t1 into the memory address resulting from adding 32 to the contents of register $t2.

Instruction Encoding

MIPS instructions are 32 bits long and follow a specific encoding format. For SW instructions, the encoding format is:

opcode (6 bits) | base_register (5 bits) | source_register (5 bits) | immediate_offset (16 bits)

Register Number Representation

In the 'sw $t1, 32($t2)' instruction, the source register is $t1 and the base register is $t2. MIPS registers have corresponding register numbers. For $t1 and $t2, their register numbers are:

  • $t1: Register number 9
  • $t2: Register number 10

Hexadecimal Representation

To encode the 'sw $t1, 32($t2)' instruction in hexadecimal, follow these steps:

  1. Determine the opcode for the SW instruction. The opcode for SW is 101011.
  2. Convert the register numbers for $t1 and $t2 to their 5-bit binary representation:
  • $t1: 01001
  • $t2: 01010
  1. Convert the immediate offset (32) to its 16-bit binary representation: 0000000000100000
  2. Concatenate the opcode, base_register, source_register, and immediate_offset: 101011 01010 01001 0000000000100000
  3. Convert the binary representation to hexadecimal: 0xAC490020

So, the hexadecimal representation of the 'sw $t1, 32($t2)' instruction is 0xAC490020.

FAQ

What is the purpose of the 'sw $t1, 32($t2)' instruction?

The 'sw $t1, 32($t2)' instruction is used to store the contents of register $t1 into a memory address specified by the sum of the contents of register $t2 and the immediate offset (32).

How is the memory address in 'sw $t1, 32($t2)' calculated?

The memory address is calculated by adding the contents of the base register ($t2) to the immediate offset (32).

What is the size of the data being stored by the 'sw $t1, 32($t2)' instruction?

The 'sw $t1, 32($t2)' instruction stores a word (32 bits) of data.

What is the opcode for the SW instruction?

The opcode for the SW instruction is 101011.

How do I convert the 'sw $t1, 32($t2)' instruction to hexadecimal?

To convert the 'sw $t1, 32($t2)' instruction to hexadecimal, follow these steps:

  1. Determine the opcode for the SW instruction.
  2. Convert the register numbers for $t1 and $t2 to binary.
  3. Convert the immediate offset (32) to binary.
  4. Concatenate the opcode, base_register, source_register, and immediate_offset.
  5. Convert the binary representation to hexadecimal.

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