Solving 'super() argument 1 must be type, not classobj' Error in Python Code

If you have encountered the error message "super() argument 1 must be type, not classobj" while working with Python code, you are not alone. This error can occur when you are trying to use the super() function to call a method in a parent class, but the arguments you are passing in are incorrect. In this guide, we will provide you with a step-by-step solution to fix this error.

Understanding the Error Message

Before we dive into the solution, it's important to understand what the error message is telling us. The "super()" function in Python is used to call a method in a parent class. The first argument to the super() function should be the subclass that you are working with, and the second argument should be an instance of that subclass. The error message "super() argument 1 must be type, not classobj" occurs when the first argument is not a type object.

Step-by-Step Solution

To fix the "super() argument 1 must be type, not classobj" error, follow these steps:

Check that the first argument to the super() function is a type object. A type object is a class, and it should be passed in as follows:

class Subclass(ParentClass):
    def __init__(self, arg):
        super(Subclass, self).__init__(arg)

In this example, "Subclass" is the type object that is passed as the first argument to the super() function.

If the first argument is correct, check that the second argument is an instance of the subclass. The second argument to the super() function should be an instance of the subclass that you are working with. It should be passed in as follows:

class Subclass(ParentClass):
    def __init__(self, arg):
        super(Subclass, self).__init__(arg)
        self.arg = arg

subclass_instance = Subclass("example")

In this example, "subclass_instance" is an instance of the "Subclass" class that is passed as the second argument to the super() function.

If both arguments are correct, check that the parent class has a method with the same name as the method you are trying to call. The super() function looks for the method in the parent class that has the same name as the method you are trying to call. If the method does not exist in the parent class, you will get an error.

class ParentClass:
    def __init__(self, arg):
        self.arg = arg

class Subclass(ParentClass):
    def __init__(self, arg):
        super(Subclass, self).__init__(arg)
        self.arg = arg

subclass_instance = Subclass("example")

In this example, the ParentClass does not have a method with the same name as the init() method in the Subclass, so you will get an error.

  1. If the parent class does not have a method with the same name, you can either rename the method in the subclass or add the method to the parent class.

FAQ

Why am I getting the "super() argument 1 must be type, not classobj" error?

This error occurs when the first argument to the super() function is not a type object.

How do I fix the "super() argument 1 must be type, not classobj" error?

To fix the error, make sure that the first argument to the super() function is a type object.

What is a type object in Python?

A type object is a class. It should be passed in as the first argument to the super() function.

What is the second argument to the super() function?

The second argument should be an instance of the subclass that you are working with.

What should I do if the parent class does not have a method with the same name?

You can either rename the method in the subclass or add the method to the parent class.

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